Java类实例化时的执行顺序

来源：互联网发布：linux运维笔记编辑：程序博客网时间：2024/04/30 10:07

public class StaticTest{    public static int k = 0;    public static StaticTest t1 = new StaticTest("t1");    public static StaticTest t2 = new StaticTest("t2");    // public StaticTest t3 = new StaticTest("t3");//循环创建本类对象导致堆内存溢出    public static int i = print("i");    public static int n = 99;    public int j = print("j");    {        print("构造快");    }    static    {        print("静态块");    }    public StaticTest(String str)    {        System.out.println((++k) + ":" + str + " i=" + i + " n=" + n);        ++n;        ++i;    }    public static int print(String str)    {        System.out.println((++k) + ":" + str + " i=" + i + " n=" + n);        ++i;        return ++n;    }    public static void main(String[] args)    {        StaticTest t = new StaticTest("init");    }}

1:j i=0 n=0
2:构造快 i=1 n=1
3:t1 i=2 n=2
4:j i=3 n=3
5:构造快 i=4 n=4
6:t2 i=5 n=5
7:i i=6 n=6
8:静态块 i=7 n=99
9:j i=8 n=100
10:构造快 i=9 n=101
11:init i=10 n=102

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