剑指offer--面试题11：旋转数组的最小数字

#include<stdio.h>#include<iostream>using namespace std;int MinInOrder(int *a,int low,int high){int result=a[low];for(int i=low+1;i<=high&&a[i]<result;++i)result=a[i];return result;}int Min(int *a,int length){if(a==NULL||length<=0)throw new std::exception("Invalid parameters");for(int low=0,high=length-1,mid=low;a[low]>=a[high];){if(high-low==1)return a[high];mid=(low+high)/2;if(a[low]==a[high]&&a[mid]==a[low])return MinInOrder(a,low,high);if(a[mid]>=a[low])low=mid;if(a[mid]<=a[high])high=mid;}}void main(){int a[6]={3,4,5,6,1,2};printf("旋转数组{3,4,5,6,1,2}的最小数字是：%d\n",Min(a,6));int b[7]={1,2,0,1,1,1,1};printf("旋转数组{1,2,0,1,1,1,1}的最小数字是：%d\n",Min(b,6));printf("空指针测试：%d\n",Min(NULL,0));}