leetcode 492. Construct the Rectangle

原题：

492. Construct the Rectan

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For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.
2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.

You need to output the length L and the width W of the web page you designed in sequence.

Example:

Input: 4Output: [2, 2]Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

Note:

1. The given area won't exceed 10,000,000 and is a positive integer
2. The web page's width and length you designed must be positive integers。

原题的意思就是找两个最相近的乘机等于area的数而已。

int* constructRectangle(int area, int* returnSize) {    int* result;    result = (int*)malloc(sizeof(int)*2);    *returnSize=2;    double sq = sqrt(area);    for(int n=(int)sq;n>0;n--)    {        if(((float)area/n-(int)area/n)==0)        {            *result=(int)area/n;            *(result+1)=n;            return result;        }    }    return result;}

这个还是比较简单那的。