leetcode 492. Construct the Rectangle

For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.
2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.

You need to output the length L and the width W of the web page you designed in sequence.

Example:

Input: 4Output: [2, 2]Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

Note:

1. The given area won't exceed 10,000,000 and is a positive integer
2. The web page's width and length you designed must be positive integers.

这一题是水题，而且大神的解法跟我的一毛一样，开心。

package leetcode;import java.util.Arrays;public class Construct_the_Rectangle_492 {public int[] constructRectangle(int area) {int [] result=new int[2];int width=(int)Math.floor(Math.sqrt(area));int length=0;while(width>=1){if(area%width!=0){width--;}else{length=area/width;break;}}result[0]=length;result[1]=width;return result;}public static void main(String[] args) {// TODO Auto-generated method stubConstruct_the_Rectangle_492 c=new Construct_the_Rectangle_492();System.out.println(Arrays.toString(c.constructRectangle(4)));}}