java ip排序实例

public class IPSort {public static void main(String[] args) {// IP 排序// 10.2.9.48, 192.168.1.2, 202.155.10.2, 173.68.46.65String[] ips = {"19.2.9.48", "192.168.1.2", "202.155.10.2", "173.68.46.65"};//------------------------------------------------------------------//Arrays.sort排序，根据字符排序，所以必须是同样的位数。否则如下例子/*Arrays.sort( ips );   //做排序  ...for( int i=0; i<ips.length; i++ ){System.out.println( ips[i] );}*///结果为：173.68.46.65 , 19.2.9.48 , 192.168.1.2 , 202.155.10.2//------------------------------------------------------------------for( int i=0; i<ips.length; i++ ){//补零操作, 为什么要补两个零, 考虑的位数是 1 位, 所以要被两个零ips[i] = ips[i].replaceAll( "(\\d+)", "00$1" );//System.out.println( ips[i] );//截成三个位, 限定后面的一定要有三位数, 前面我不管(会被截断)ips[i] = ips[i].replaceAll( "0*(\\d{3})", "$1" );//System.out.println( ips[i] );}Arrays.sort( ips );   //做排序  ...for( int i=0; i<ips.length; i++ ){System.out.println( ips[i] );}//去零处理 ...for( int i=0; i<ips.length; i++ ){ips[i] = ips[i].replaceAll( "0*(\\d+)", "$1" );System.out.println( ips[i] );}}}