PAT (Advanced Level) Practise 1058 A+B in Hogwarts (20)

1058. A+B in Hogwarts (20)

时间限制

50 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 10⁷], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

题意：给你两个数，每个数由三个数组成，第三个数是29进制，第二个数是17进制，求出他们的和

#include <iostream>#include <cstdio>#include <cstring>#include <string>#include <algorithm>#include <cmath>#include <map>#include <set>#include <stack>#include <queue>#include <vector>#include <bitset>using namespace std;#define LL long longconst int INF = 0x3f3f3f3f;int main(){int a1,b1,c1,a2,b2,c2,a3,b3,c3 ;while (~scanf("%d.%d.%d", &a1, &b1, &c1)){scanf("%d.%d.%d", &a2, &b2, &c2);int cnt = (c1 + c2) / 29;c3 = (c1 + c2) % 29;b3 = (b1 + b2 + cnt) % 17;cnt = (b1 + b2 + cnt) / 17;a3 = a1 + a2 + cnt;printf("%d.%d.%d\n", a3, b3, c3);}return 0;}