【c++】PAT(advanced level)1058. A+B in Hogwarts (20)
来源:互联网 发布:linux卸载搜狗输入法 编辑:程序博客网 时间:2024/06/03 20:11
1058. A+B in Hogwarts (20)
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:3.2.1 10.16.27Sample Output:
14.1.28
#include<iostream>#include<string>using namespace std;int main(){int a[3],b[3];char c;cin>>a[0]>>c>>a[1]>>c>>a[2];cin>>b[0]>>c>>b[1]>>c>>b[2];int ff=0;a[2]=a[2]+b[2];if(a[2]>=29){a[1]++;a[2]-=29;}a[1]=a[1]+b[1];if(a[1]>=17){a[0]++;a[1]-=17;}a[0]=a[0]+b[0];cout<<a[0]<<"."<<a[1]<<"."<<a[2];return 0;}
- 【c++】PAT(advanced level)1058. A+B in Hogwarts (20)
- 【PAT (Advanced Level)】1058. A+B in Hogwarts (20)
- 【PAT】【Advanced Level】1058. A+B in Hogwarts (20)
- PAT (Advanced Level) Practise 1058 A+B in Hogwarts (20)
- PAT (Advanced Level) Practise 1058 A+B in Hogwarts (20)
- PAT (Advanced Level) 1058. A+B in Hogwarts (20) 字符串相加
- 1058. A+B in Hogwarts (20)【水题】——PAT (Advanced Level) Practise
- Pat(Advanced Level)Practice--1058(A+B in Hogwarts)
- 1058. A+B in Hogwarts (20)- PAT
- 【PAT】1058. A+B in Hogwarts (20)
- PAT 1058. A+B in Hogwarts (20)
- PAT 1058. A+B in Hogwarts (20)
- pat 1058. A+B in Hogwarts (20)
- PAT 1058. A+B in Hogwarts (20)
- PAT 1058. A+B in Hogwarts (20)
- PAT---1058. A+B in Hogwarts (20)
- PAT-A 1058. A+B in Hogwarts
- PAT A 1058. A+B in Hogwarts (20)
- ZJU 3757 模拟坑题
- 求正整数n所有可能的和式的组合
- [LeetCode]Integer to Roman
- hdu2586 step5.3.4.cpp How far away ?
- 我是——
- 【c++】PAT(advanced level)1058. A+B in Hogwarts (20)
- 链表操作
- 【剑指offer】链表相关-反转链表&&递归实现16
- C#中对文件的上传下载操作总结(下载后点击删除按钮总是提示进程被占用)
- Cassandra学习笔记之Gossip协议
- 重载运算符排序
- 深入学习FastDB
- server第一次入门
- C++整型和字符串转换