poj2503 Babelfish（map，二分）

You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.

Input

Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.

Output

Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".

Sample Input

dog ogdaycat atcaypig igpayfroot ootfrayloops oopslayatcayittenkayoopslay

Sample Output

catehloops

Hint

Huge input and output,scanf and printf are recommended.

 

这个英文不难看懂，题也比较水，把它放到博客上的原因只是为了复习下map的用法

map版代码

#include<iostream>#include<cstdio>#include<cmath>#include<string>#include<cstdlib>#include<algorithm>#include<map>const int MAXN=100005;using namespace std;map<string,string> dic;string t1,t2; char f;//这道题让我先用map水过去，哈哈哈哈int main(){    while(true)    {        cin>>t1;        f=getchar();        if(f=='\r'||f=='\n') break;        cin>>t2;        dic[t2]=t1;    }    if(dic.count(t1)) cout<<dic[t1]<<endl;    else printf("eh\n");    while(cin>>t1)    {        if(dic.count(t1)) cout<<dic[t1]<<endl;        else printf("eh\n");    }}

超级短，所以二分的代码以后来补啦~

说个思路：对于当地的单词按字典序排序，并且在排序之前记录一个标号来对应自己的语言，然后就二分查找啦~