Babelfish Poj2503(STL map的使用)

Babelfish

Time Limit: 3000MS Memory Limit: 65536KTotal Submissions: 41561 Accepted: 17638

Description

You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.

Input

Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.

Output

Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".

Sample Input

dog ogdaycat atcaypig igpayfroot ootfrayloops oopslayatcayittenkayoopslay

Sample Output

catehloops

Hint

Huge input and output,scanf and printf are recommended.

思路 : 存入map 查找输出0.0  裸裸STL 好害羞2333333.....

#include <iostream>#include <map>#include <cstdio>#include <string>using namespace std;int main(){    char Key[66], Find[66];    char str[66];    map<string,string>mp;    while (gets(str)&&str[0]!='\0') ///空行的控制    {        sscanf(str,"%s %s",Key,Find); ///sscanf按格式从a读串        mp[Find]=Key;    }    while (gets(str)&&str[0]!='\0')    {        sscanf(str,"%s",Find);        if (mp[Find]!="\0") ///int初始是0 string为'\0'        {            cout<<mp[Find]<<endl;        }        else        {            cout<<"eh"<<endl;        }///        map<string,string>::iterator(迭代器) x ; find()目测从头迭代///        if (mp.find(Find)==mp.end())  ///到end时说明没有找到要找的元素///        {///            cout<<"eh"<<endl;///        }///        else///        {///            cout<<mp[Find]<<endl; ///map 类似二位数组///        }///注释方法也对    }    return 0;}