oracle 两个字符串根据指定分割符分割后比较方法

来源:互联网 发布:全志科技 知乎 编辑:程序博客网 时间:2024/06/08 00:39
CREATE OR REPLACE function fun_getEqualsByParams(aParam varchar2,antherParam varchar2) return varchar2 is
Result varchar2(5):='true';----返回 true 或者 false

CURSOR cur_aParam IS
        WITH A AS
          (SELECT aParam A FROM DUAL)
        SELECT REGEXP_SUBSTR(A,'[^;]+',1,LEVEL) personStr FROM A
        CONNECT BY LEVEL<=LENGTH(A)-LENGTH(REPLACE(A,';'))+1;
       
CURSOR cur_antherParam IS  
        WITH B AS
          (SELECT antherParam B FROM DUAL)     
        SELECT REGEXP_SUBSTR(B,'[^;]+',1,LEVEL) personStr  FROM B
        CONNECT BY LEVEL<=LENGTH(B)-LENGTH(REPLACE(B,';'))+1;                 

begin   
   
    FOR curA IN cur_aParam LOOP--------遍历第一个字符串是否在第二个字符串中
        IF INSTR(antherParam,curA.personStr)=0  THEN
            Result:='false';
            RETURN Result;       
        END IF;
    END LOOP;
 
 
    FOR curB IN cur_antherParam LOOP--------遍历第二个字符串是否在第一个字符串中
        IF INSTR(aParam,curB.personStr)=0  THEN
            Result:='false';
            RETURN Result;       
        END IF;
    END LOOP;

    RETURN Result;

end fun_getEqualsByParams;
阅读全文
0 0