对List集合嵌套了map集合的排序

来源：互联网发布：上海软件项目经理工资编辑：程序博客网时间：2024/05/21 17:32
如题，一个List<Map<String, String>> Lists = new ArrayList<Map<String, String>>();怎么才能对它进行排序呢？通过函数Collections.sort进行排列：private String[] namelist = {"Id", "UserId", "UserNo", "Name", "TypeId", "Money", "Remark", "PassCode", "Order_no", "AddTime"};private String[] keylist = {"id", "userid", "username", "name", "type", "money", "remark", "passcode", "ordernumber", "addtime"};

id是我map里面的字段，是自增的 Collections.sort(str, new Comparator<Map<String, String>>() {                            @Override                            public int compare(Map<String, String> o1, Map<String, String> o2) {                                String n1=o1.get("id");                                String n2=o2.get("id");//                                我这里是从大到小的排序，如果从小到大，n1和n2换一下位置就可以了                                return n2.compareTo(n1);                            }                        });                        



然后使用增强for循环遍历出整个map集合所有数据的
List<Map<String, String>> list=new ArrayList<Map<String, String>>();for (Map<String,String> map:str){    list.add(map);}




我这里的数据是要匹配到listview上的，所以添加到新的list之后，直接用适配器直接适配上去                    public void doResults(List<Map<String, String>> str) {                            if (moneyList != null) {                                moneyList.clear();                            }                        Collections.sort(str, new Comparator<Map<String, String>>() {                            @Override                            public int compare(Map<String, String> o1, Map<String, String> o2) {                                String n1=o1.get("id");                                String n2=o2.get("id");//                                我这里是从大到小的排序，如果从小到大，n1和n2换一下位置就可以了                                return n2.compareTo(n1);                            }                        });                                                List<Map<String, String>> list=new ArrayList<Map<String, String>>();                        for (Map<String,String> map:str){                            list.add(map);                        }                            moneyList.addAll(list);                            adapter = new MoneyAdapter(MoneyChargeActivity.this, moneyList);                            mXListView.setAdapter(adapter);
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