HDU 1037理解题目即AC
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Keep on Truckin’
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 14872 Accepted Submission(s): 10222Problem Description
Boudreaux and Thibodeaux are on the road again …“Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!”
“Don’t worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!”
“We’re not going to make it, I say!”
So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?
Input
Input to this problem will consist of a single data set. The data set will be formatted according to the following description.The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.
Output
There will be exactly one line of output. This line will be:NO CRASH
if the height of the 18-wheeler is less than the height of each of the underpasses, or:
CRASH X
otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.Sample Input
180 160 170Sample Output
CRASH 160
思路
说实话这种简单的题目,如果花了5分钟或10分钟来读懂题目,真的有点不值得,所以自己稍微总结了点读题目的小经验
1、先看输入输出。这道题看输入是输入3个整数,输出的输出最小的那个整数。所以脑子里会有一种反应就是会不会输入三个数输出最小的数。
2、然后看问题的描述,输入输出的描述、还会看到18楼是168英寸。所以就很容易得出程序应该要我表达什么意思了
3、题意:输入三个数,如果三个数中有比168小的就输出CRASH %d,如果没有则输出NO CRASH。
代码
#include <iostream>using namespace std;int main(){ int a,b,c; int l; int k[3]={0}; cin>>a>>b>>c; if(a>168&&b>168&&c>168) cout<<"NO CRASH"<<endl; if(a<168) k[0]=a; if(b<168) k[1]=b; if(c<168) k[2]=c; for(int i=0;i<3;i++) { if(k[i]!=0) cout<<"CRASH"<<" "<<k[i]<<endl; } return 0;}
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