【PAT】【Advanced Level】1041. Be Unique (20)

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1041. Be Unique (20)

时间限制
100 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue

Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1, 104]. The first one who bets on a unique number wins. For example, if there are 7 people betting on 5 31 5 88 67 88 17, then the second one who bets on 31 wins.

Input Specification:

Each input file contains one test case. Each case contains a line which begins with a positive integer N (<=105) and then followed by N bets. The numbers are separated by a space.

Output Specification:

For each test case, print the winning number in a line. If there is no winner, print "None" instead.

Sample Input 1:
7 5 31 5 88 67 88 17
Sample Output 1:
31
Sample Input 2:
5 888 666 666 888 888
Sample Output 2:
None
原题链接:

https://www.patest.cn/contests/pat-a-practise/1041

思路:

设数组储存个数

最后从前到后判断

CODE:

#include<iostream>#include<cstring>using namespace std;int bo[10001];int nu[100001];int main(){    memset(bo,0,sizeof(bo));    int n;    cin>>n;    int s=0;    for (int i=0;i<n;i++)    {        cin>>nu[i];        bo[nu[i]]++;    }    for (int i=0;i<n;i++)        if(bo[nu[i]]==1)    {        cout<<nu[i];        s=1;        break;    }    if (s==0) cout<<"None";    return 0;}



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