PAT (Advanced Level) Practise 1041 Be Unique (20)
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1041. Be Unique (20)
时间限制
100 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue
Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1, 104]. The first one who bets on a unique number wins. For example, if there are 7 people betting on 5 31 5 88 67 88 17, then the second one who bets on 31 wins.
Input Specification:
Each input file contains one test case. Each case contains a line which begins with a positive integer N (<=105) and then followed by N bets. The numbers are separated by a space.
Output Specification:
For each test case, print the winning number in a line. If there is no winner, print "None" instead.
Sample Input 1:7 5 31 5 88 67 88 17Sample Output 1:
31Sample Input 2:
5 888 666 666 888 888Sample Output 2:
None
输出最先出现的只出现一次的数,直接统计每个数的出现次数就好了
#include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<queue> using namespace std;typedef long long ll;const int maxn = 1e5 + 5;int f[maxn], n, a[maxn];int main(){scanf("%d", &n);for (int i = 0; i < n; i++) scanf("%d", &a[i]), f[a[i]]++;for (int i = 0; i < n; i++){if (f[a[i]] == 1) { printf("%d\n", a[i]); return 0; }}printf("None\n");return 0;}
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