leetcode--Isomorphic Strings

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Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg""add", return true.

Given "foo""bar", return false.

Given "paper""title", return true.

Note:
You may assume both s and t have the same length.

[java] view plain copy
  1. import java.util.Arrays;  
  2. public class Solution {  
  3.     public boolean isIsomorphic(String s, String t) {  
  4.         if(s.length()!=t.length()) return false;  
  5.         int[] map1 = new int[257];    
  6.         int[] map2 = new int[257];        
  7.         Arrays.fill(map1, -1);  
  8.         Arrays.fill(map2, -1);  
  9.         for(int i=0;i<s.length();i++){  
  10.             if(map1[s.charAt(i)]==-1){  
  11.                 map1[s.charAt(i)] = t.charAt(i);  
  12.             }else{  
  13.                 if(map1[s.charAt(i)] != t.charAt(i)){  
  14.                     return false;  
  15.                 }  
  16.             }  
  17.             if(map2[t.charAt(i)]==-1){  
  18.                 map2[t.charAt(i)] = s.charAt(i);  
  19.             }else{  
  20.                 if(map2[t.charAt(i)] != s.charAt(i)){  
  21.                     return false;  
  22.                 }  
  23.             }  
  24.         }         
  25.         return true;  
  26.     }  

原文链接http://blog.csdn.net/crazy__chen/article/details/45439841

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