使用SAX解析XML文件(SAX解析)

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首先我的XML文件名为a.xml，路径在项目目录下，内容如下：

实现代码如下：

import java.io.IOException;import javax.xml.parsers.ParserConfigurationException;import javax.xml.parsers.SAXParser;import javax.xml.parsers.SAXParserFactory;import org.xml.sax.Attributes;import org.xml.sax.SAXException;import org.xml.sax.helpers.DefaultHandler;public class SAXDemo {public static void test1(){SAXParserFactory factory = SAXParserFactory.newInstance();try {SAXParser parser = factory.newSAXParser();DefaultHandlerDemo defaultHandler = new DefaultHandlerDemo();parser.parse("a.xml", defaultHandler);} catch (ParserConfigurationException e) {// TODO Auto-generated catch blocke.printStackTrace();} catch (SAXException e) {// TODO Auto-generated catch blocke.printStackTrace();} catch (IOException e) {// TODO Auto-generated catch blocke.printStackTrace();}}public static void main(String[] args) {test1();}}class DefaultHandlerDemo extends DefaultHandler{@Overridepublic void startDocument() throws SAXException {System.out.println("开始解析XML文件。。。");}@Overridepublic void endDocument() throws SAXException {System.out.println("已解析完成。。。");}@Overridepublic void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException {System.out.println("元素名称"+qName);for (int i = 0; i < attributes.getLength(); i++) {System.out.println(attributes.getQName(i)+"="+attributes.getValue(i));}}@Overridepublic void characters(char[] ch, int start, int length) throws SAXException {String content = new String(ch, start, length);System.out.println(content);}}

实现效果如下：

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