UVA 10038
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A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n − 1. For instance,
1 4 2 3
is a jolly jumper, because the absolutes differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.
Input
Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.
Output
For each line of input, generate a line of output saying ‘Jolly’ or ‘Not jolly’.
Sample Input
4 1 4 2 3
5 1 4 2 -1 6
Sample Output
Jolly
Not jolly
题意:给定一个整数n,有一个长度为n的整数序列,如果这个序列相邻两个整数之间的差的绝对值均在1到n-1之间,并且这之间的每个数字都只出现一次,那么这个序列叫做Jolly Jumpers。
思路:首先把这n个数字存到数组或者栈中,每次两两比较这两个数,用一个数组记录出现的所有数字的次数;这个题目最重要的一步就是判断1到n-1出现的数字,如果两数字的绝对值差出现的次数大于一次或者其差不在1到n-1之间,那么可以判断不满足题意,否则,符合题意。
注意:需要注意的是,题目并没有告诉我们序列中数字的大小,所以使用int类型会出现runtime error的错误,需要使用long类型。
#include <cstdio>#include <stack>#include <memory.h>#include <cstdlib>using namespace std;int main(){ int cnt[3005]; int n; while(~scanf("%d", &n)){ long a, b, k; bool isJolly = true; stack<long> num; memset(cnt, 0, sizeof(int)*n); k = n; while(k--){ long x; scanf("%ld", &x); num.push(x); } for(int i = 1; i < n; i++){ a = num.top(); num.pop(); b = num.top(); long diff = labs(a-b); cnt[diff]++; if(cnt[diff] > 1 || diff < 1 || diff > n-1){ isJolly = false; break; } } if(isJolly) printf("Jolly\n"); else printf("Not jolly\n"); } return 0;}
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