leetcode 659. Split Array into Consecutive Subsequences

原题：

You are given an integer array sorted in ascending order (may contain duplicates), you need to split them into several subsequences, where each subsequences consist of at least 3 consecutive integers. Return whether you can make such a split.

Example 1:

Input: [1,2,3,3,4,5]Output: TrueExplanation:You can split them into two consecutive subsequences : 1, 2, 33, 4, 5

Example 2:

Input: [1,2,3,3,4,4,5,5]Output: TrueExplanation:You can split them into two consecutive subsequences : 1, 2, 3, 4, 53, 4, 5

Example 3:

Input: [1,2,3,4,4,5]Output: False

Note:

1. The length of the input is in range of [1, 10000]

写个这个玩意还真是费尽。。。

代码如下：

bool isPossible(int* nums, int numsSize) {    if(numsSize<3)        return false;    struct listnode    {        int lastnum;        int count;    };    struct listnode* test;    test=(struct listnode*)malloc(sizeof(struct listnode)*20000);    int amount=0;    for(int n=0;n<numsSize;n++)    {        int flag=1;        for(int m=amount-1;m>=0;m--)        {            if((test+m)->lastnum==(*(nums+n)-1))            {                flag=0;                (test+m)->lastnum+=1;                (test+m)->count+=1;                break;            }        }        if(flag==1)        {            (test+amount)->lastnum=*(nums+n);            (test+amount)->count=1;            amount++;        }    }    for(int n=0;n<amount;n++)    {        //printf("F%d",(test+n)->count);        if((test+n)->count<3)            return false;    }    return true;}

就是构建几个桶一样，往里面扔数字，规则就是从后往前（时间顺序）。

最后检索有没有桶不够三个。

得出结论。