poj_1611_模拟递推_刚做过类似

The Suspects

Severe acute respiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, was recognized as a global threat in mid-March 2003. To minimize transmission to others, the best strategy is to separate the suspects from others.
In the Not-Spreading-Your-Sickness University (NSYSU), there are many student groups. Students in the same group intercommunicate with each other frequently, and a student may join several groups. To prevent the possible transmissions of SARS, the NSYSU collects the member lists of all student groups, and makes the following rule in their standard operation procedure (SOP).
Once a member in a group is a suspect, all members in the group are suspects.
However, they find that it is not easy to identify all the suspects when a student is recognized as a suspect. Your job is to write a program which finds all the suspects.
Input
The input file contains several cases. Each test case begins with two integers n and m in a line, where n is the number of students, and m is the number of groups. You may assume that 0 < n <= 30000 and 0 <= m <= 500. Every student is numbered by a unique integer between 0 and n−1, and initially student 0 is recognized as a suspect in all the cases. This line is followed by m member lists of the groups, one line per group. Each line begins with an integer k by itself representing the number of members in the group. Following the number of members, there are k integers representing the students in this group. All the integers in a line are separated by at least one space.
A case with n = 0 and m = 0 indicates the end of the input, and need not be processed.
Output
For each case, output the number of suspects in one line.
Sample Input
100 4
2 1 2
5 10 13 11 12 14
2 0 1
2 99 2
200 2
1 5
5 1 2 3 4 5
1 0
0 0
Sample Output
4
1
1

题意:
给你n个拼接块,告诉你l , m大小,拼接块左下方有l个凹陷,右下方有m凹陷, 左上方有l个突起,右上方有个突起,不可旋转,凹陷和突起可以结合,求最多拼接几个拼接块;

思路:
对其中一条边从大到小排序,然后遍历求到当前拼接块可以最大拼接几个
类似题目

#include<iostream>#include<cstdio>#include<cstring>#include<map>#include<algorithm>using namespace std;typedef long long ll;const int N=9999;struct node{int x,y; }num[11111];bool cmp(node a,node b){    if(a.x==b.x)        return a.y>b.y;    return a.x>b.x;}int main(){    int n,i,j;    while(cin>>n)    {        if(n==0)        {            puts("*");            break;        }        for(i=0;i<n;i++)            scanf("%d%d",&num[i].x,&num[i].y);        sort(num,num+n,cmp);        int dp[11111]={0};        for(i=0;i<n;i++)        {            dp[i]=1;           for(j=0;j<i;j++)            {                if(num[j].x>=num[i].x && num[j].y>=num[i].y)                    dp[i]=max(dp[i],dp[j]+1);            }        }        int ans=0;        for(i=0;i<n;i++)            ans=max(ans,dp[i]);        cout<<ans<<endl;    }    return 0;}/*a s  d   f    a     s      s      */