CodeForces 830B Cards Sorting(set乱搞)
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题目链接:http://codeforces.com/problemset/problem/830/B点击打开链接
Vasily has a deck of cards consisting of n cards. There is an integer on each of the cards, this integer is between1 and 100 000, inclusive. It is possible that some cards have the same integers on them.
Vasily decided to sort the cards. To do this, he repeatedly takes the top card from the deck, and if the number on it equals the minimum number written on the cards in the deck, then he places the card away. Otherwise, he puts it under the deck and takes the next card from the top, and so on. The process ends as soon as there are no cards in the deck. You can assume that Vasily always knows the minimum number written on some card in the remaining deck, but doesn't know where this card (or these cards) is.
You are to determine the total number of times Vasily takes the top card from the deck.
The first line contains single integer n (1 ≤ n ≤ 100 000) — the number of cards in the deck.
The second line contains a sequence of n integersa1, a2, ..., an (1 ≤ ai ≤ 100 000), where ai is the number written on thei-th from top card in the deck.
Print the total number of times Vasily takes the top card from the deck.
46 3 1 2
7
11000
1
73 3 3 3 3 3 3
7
In the first example Vasily at first looks at the card with number 6 on it, puts it under the deck, then on the card with number 3, puts it under the deck, and then on the card with number 1. He places away the card with 1, because the number written on it is the minimum among the remaining cards. After that the cards from top to bottom are[2, 6, 3]. Then Vasily looks at the top card with number2 and puts it away. After that the cards from top to bottom are[6, 3]. Then Vasily looks at card 6, puts it under the deck, then at card 3 and puts it away. Then there is only one card with number6 on it, and Vasily looks at it and puts it away. Thus, in total Vasily looks at7 cards.
这样一来维护当前取牌的位置和寻找下一个需要取得位置 如果不需要循环则不需要加上牌堆数 如果需要则加上失败数量
set保存每个点的出现位置 然后lowerbound二分寻找下一个数的位置 如果找不到则说明需要进行循环
#include <bits/stdc++.h>#define maxn 100005using namespace std;set<int > point[maxn];set<int > ::iterator it ;int a[maxn];int main(){ int n;int total; cin >> n; for(int i=1;i<=n;i++) { cin >> a[i]; point[a[i]].insert(i); } total=n; long long int ans=n; int mid=0; sort(a+1,a+1+n); for(int i=1;i<=n;i++) { int now=a[i]; it=point[now].lower_bound(mid); if(it==point[now].end()) { ans+=total; mid=0; it=point[now].lower_bound(mid); } mid=(*it); point[now].erase(it); total--; } cout <<ans << endl;}
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