python实现给定一个单链表删除指定节点

题目：

初始化定义一个单链表，删除指定节点，输出链表

下面是具体的实现：

#!usr/bin/env python#encoding:utf-8'''__Author__:沂水寒城功能：给定一个单链表删除指定节点'''class Node(object):    '''    节点类    '''    def __init__(self,data):        self.num=data        self.next=Noneclass DeleteNode():    '''    实现删除指定节点功能    '''    def delete_node(self,node):        node.num=node.next.num         node.next=node.next.next class PrintNode():    '''    输出指定节点为起始节点的链表    '''    def print_node(self,node):        res_list=[]        while node:            res_list.append(str(node.num))            node=node.next        print '->'.join(res_list)if __name__ == '__main__':    node1=Node(90)    node2=Node(34)    node3=Node(89)    node4=Node(77)    node5=Node(23)    node1.next=node2     node2.next=node3    node3.next=node4    node4.next=node5    print 'init single linknode is:'    printnode=PrintNode()    printnode.print_node(node1)    delete=DeleteNode()    delete.delete_node(node4)    print 'after delete node,the single linknode is:'    printnode.print_node(node1)

结果如下：

init single linknode is:90->34->89->77->23after delete node,the single linknode is:90->34->89->23[Finished in 0.3s]