简单的KNN的python实现

import mathmovie_data = {"宝贝当家": [45, 2, 9, "喜剧片"],                "美人鱼": [21, 17, 5, "喜剧片"],                "澳门风云3": [54, 9, 11, "喜剧片"],                "功夫熊猫3": [39, 0, 31, "喜剧片"],                "谍影重重": [5, 2, 57, "动作片"],                "叶问3": [3, 2, 65, "动作片"],                "伦敦陷落": [2, 3, 55, "动作片"],                "我的特工爷爷": [6, 4, 21, "动作片"],                "奔爱": [7, 46, 4, "爱情片"],                "夜孔雀": [9, 39, 8, "爱情片"],                "代理情人": [9, 38, 2, "爱情片"],                "新步步惊心": [8, 34, 17, "爱情片"]}x=[23,3,17]KNN=[]for key,v in movie_data.items():    d = math.sqrt((x[0] - v[0]) ** 2 + (x[1] - v[1]) ** 2 + (x[2] - v[2]) ** 2)      KNN.append([key, round(d, 2)])print(KNN)KNN.sort(key=lambda dis: dis[1])KNN=KNN[:5]labels = {"喜剧片":0,"动作片":0,"爱情片":0}  for s in KNN:      label = movie_data[s[0]]      labels[label[3]] += 1  labels =sorted(labels.items(),key=lambda l: l[1],reverse=True)  print(labels,labels[0][0],sep='\n')