java中带变量的json格式数据用string拼接示例

来源:互联网 发布:心徹为知,循道而为 编辑:程序博客网 时间:2024/06/01 19:46

String json = "{" + "\"component_appid\":" + "\"" + componentConfig.getAppid() + "\"," + "\"component_appsecret\":" + "\"" + componentConfig.getAppsecret() + "\"," + "\"component_verify_ticket\":" + "\"" +componentConfig.getTicket() + "\"}";

System.out.println("返回json:"+json);

输出格式:{"component_appid":"wx57cf8b","component_appsecret":"c67c4ad473616888","component_verify_ticket":"ticket@@@LMZE6aWh9ydJ6rGIs7d_B6YygiKGXni_-LNL_urw8WVUDz_TzX2B5yaD7IC6Q"}

原创粉丝点击