判断字符串是否包含Emoji表情

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/** * Created by king on 2017/3/6. * * 判断字符串是否包含Emoji表情 */public class ContainsEmojiUtils {    public static boolean containsEmoji(String source) {        int len = source.length();        boolean isEmoji = false;        for (int i = 0; i < len; i++) {            char hs = source.charAt(i);            if (0xd800 <= hs && hs <= 0xdbff) {                if (source.length() > 1) {                    char ls = source.charAt(i + 1);                    int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;                    if (0x1d000 <= uc && uc <= 0x1f77f) {                        return true;                    }                }            } else {                // non surrogate                if (0x2100 <= hs && hs <= 0x27ff && hs != 0x263b) {                    return true;                } else if (0x2B05 <= hs && hs <= 0x2b07) {                    return true;                } else if (0x2934 <= hs && hs <= 0x2935) {                    return true;                } else if (0x3297 <= hs && hs <= 0x3299) {                    return true;                } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50 || hs == 0x231a) {                    return true;                }                if (!isEmoji && source.length() > 1 && i < source.length() - 1) {                    char ls = source.charAt(i + 1);                    if (ls == 0x20e3) {                        return true;                    }                }            }        }        return isEmoji;    }}-----------------------------------------------------------if(ContainsEmojiUtils.containsEmoji(etQuestionContent.getText().toString())){    ToastUtils.showSafeToast("内容含有表情符，请重新输入");}
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