UVa 11947

来源：互联网发布：三层网络结构编辑：程序博客网时间：2024/05/16 19:20

题目：计算孩子出生的日期以及对应的星座，已知最后经期的日期，预产期是它后面的第四周（280天）。

分析：模拟。按照要求求出280天后的日期和对应的星座。

需要注意：1.闰年；

2.计算结果会跨年，也要判断是不是闰年；

说明：注意输出的月份和日期是两位，不足补零。

#include <stdio.h>#include <stdlib.h>int get_number(char str[], int s, int e){int value = 0;for (int i = s; i <= e; ++ i) {value = value*10 + str[i]-'0';}return value;}int  days_of_month[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};int  zodiac_bound[13] = {0, 21, 20, 21, 21, 22, 22, 23, 22, 24, 24, 23, 23};char zodiac_name[13][13] = {"capricorn", "aquarius", "pisces", "aries", "taurus", "gemini", "cancer", "leo", "virgo", "libra", "scorpio", "sagittarius", "capricorn"};int main(){int  n;char buf[10];while (~scanf("%d",&n)) for (int i = 1; i <= n; ++ i) {scanf("%s",buf);int month = get_number(buf, 0, 1);int day   = get_number(buf, 2, 3);int year  = get_number(buf, 4, 7);// leap yeardays_of_month[2] = 28 + (year%4 == 0 && year%100 || year%400 == 0);day += 280;while (day > days_of_month[month]) {day -= days_of_month[month];month ++;// int next yearif (month > 12) {month = 1;year ++;// leap yeardays_of_month[2] = 28 + (year%4 == 0 && year%100 || year%400 == 0);}}printf("%d %02d/%02d/%04d ",i,month,day,year);if (day < zodiac_bound[month]) {printf("%s\n",zodiac_name[month-1]);}else {printf("%s\n",zodiac_name[month]);}}return 0;}

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