HDU 6197array array array(简单dp)
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array array array
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 341 Accepted Submission(s): 214
Problem Description
One day, Kaitou Kiddo had stolen a priceless diamond ring. But detective Conan blocked Kiddo's path to escape from the museum. But Kiddo didn't want to give it back. So, Kiddo asked Conan a question. If Conan could give a right answer, Kiddo would return the ring to the museum.
Kiddo: "I have an arrayA and a number k , if you can choose exactly k elements from A and erase them, then the remaining array is in non-increasing order or non-decreasing order, we say A is a magic array. Now I want you to tell me whether A is a magic array. " Conan: "emmmmm..." Now, Conan seems to be in trouble, can you help him?
Kiddo: "I have an array
Input
The first line contains an integer T indicating the total number of test cases. Each test case starts with two integers n and k in one line, then one line with n integers: A1,A2…An .
1≤T≤20
1≤n≤105
0≤k≤n
1≤Ai≤105
Output
For each test case, please output "A is a magic array." if it is a magic array. Otherwise, output "A is not a magic array." (without quotes).
Sample Input
34 11 4 3 75 24 1 3 1 26 11 4 3 5 4 6
Sample Output
A is a magic array.A is a magic array.A is not a magic array.
Source
2017 ACM/ICPC Asia Regional Shenyang Online
想法:递增递减子序列
代码:
#include <stdio.h>#include <string.h>#include <algorithm>using namespace std;int a[100005],dp[100005],n;int bin(int size,int k){ int l = 1,r = size; while(l<=r) { int mid = (l+r)/2; if(k>dp[mid]) l = mid+1; else r = mid-1; } return l;}int LIS(){ memset(dp,0,sizeof(dp)); int i,j,ans=1; dp[1] = a[1]; for(i = 2; i<=n; i++) { if(a[i]<=dp[1]) j = 1; else if(a[i]>dp[ans]) j = ++ans; else j = bin(ans,a[i]); dp[j] = a[i]; } return ans;}int LIS1(){ memset(dp,0,sizeof(dp)); int i,j,ans=1; dp[1] = a[1]; for(i = 2; i<=n; i++) { if(a[i]>dp[1]) j = 1; else if(a[i]<=dp[ans]) j = ++ans; else j = bin(ans,a[i]); dp[j] = a[i]; } return ans;}int main(){ int T; scanf("%d",&T); while(T--) { int k; scanf("%d %d",&n,&k); for(int i=1;i<=n;i++) { scanf("%d",&a[i]); } int ans1=n-LIS(); int ans2=n-LIS1(); //printf("%d %d\n",n-ans1,n-ans2); if(k>=ans1||k>=ans2) printf("A is a magic array.\n"); else printf("A is not a magic array.\n"); } return 0;}
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