ccf 炉石传说 模拟

这道题，我用的是vector来模拟战场，vector可以任意的操作和删除，所以用起来很方便。。。

100分代码：

#include<stdio.h>#include<iostream>#include<string.h>#include<vector>using namespace std;int x=30,y=30;//先手英雄 后手英雄struct act{    int pos;    int att;    int live;    act(int poss,int attt,int livee)    {        pos=poss;        att=attt;        live=livee;    }};vector<act>v0,v1;//先手战场 后首战场void update(){    for(int i=0; i<v0.size(); i++)    {        act k=v0[i];        if(k.live<=0)v0.erase(v0.begin()+i);    }   for(int i=0; i<v1.size(); i++)    {        act k=v1[i];        if(k.live<=0)v1.erase(v1.begin()+i);    }}void buid(int flag,act a){    if(flag==0)    {        v0.insert(v0.begin()+a.pos-1,1,a);    }    else    {        v1.insert(v1.begin()+a.pos-1,1,a);    }}void gg(int flag,int a,int b){    if(flag==0)    {        if(b==0)        {            y-=v0[a-1].att;        }        else        {            v0[a-1].live-=v1[b-1].att;            v1[b-1].live-=v0[a-1].att;        }    }    else    {        if(b==0)        {            x-=v1[a-1].att;        }        else        {            v1[a-1].live-=v0[b-1].att;            v0[b-1].live-=v1[a-1].att;        }    }    update();}int main(){    v0.clear();    v1.clear();    int n;    scanf("%d",&n);    int flag=0;//先手状态    string s;    int a,b,c;    for(int i=0; i<n; i++)    {        cin>>s;        if(s=="end")        {            flag=!flag;            continue;        }        else if(s=="summon")        {            scanf("%d%d%d",&a,&b,&c);            if(x<=0||y<=0)continue;            if(flag==0)            {                if(v0.size()==7)continue;            }            else            {                if(v1.size()==7)continue;            }            buid(flag,act(a,b,c));        }        else if(s=="attack")        {            scanf("%d%d",&a,&b);            if(x<=0||y<=0)continue;            gg(flag,a,b);        }    }    update();    if(x<=0)        printf("-1\n");    else if(y<=0)        printf("1\n");    else        printf("0\n");    cout<<x<<endl;    cout<<v0.size();    for(int i=0; i<v0.size(); i++)    {        cout<<" "<<v0[i].live;    }    cout<<endl;    cout<<y<<endl;    cout<<v1.size();    for(int i=0; i<v1.size(); i++)    {        cout<<" "<<v1[i].live;    }    cout<<endl;}