sgu265Wizards(计算几何)
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题意:
一个空间直角坐标系内,对一个点有三种操作:
1.平移(x,y,z)⇒(x+a,y+b,z+c);
2.缩放(x,y,z)⇒(ax,by,cz);
3.绕一个向量(x,y,z)顺时针旋转α角(角度制)。
对空间内的m个点给出n个操作,求每个点在操作后的坐标。
tip:
每次操作在之前的基础上左乘当前操作的矩阵,最后右乘每次给的初始坐标。
#include <cstdio>#include <iostream>#include <algorithm>#include <cstring>#include <cmath>using namespace std;const double PI = acos(-1.0);struct Tmatrix{ double mat[4][4]; void init(){ for(int i = 0 ;i < 4; i++)for(int j = 0 ; j < 4 ; j++) mat[i][j] = 0.0; } Tmatrix mul(Tmatrix b){ Tmatrix p; p.init(); for(int i = 0 ;i <= 3 ;i++){ for(int k = 0 ; k <= 3 ; k++){ for(int j = 0 ; j <= 3 ; j++){ p.mat[i][j] += mat[i][k]*b.mat[k][j]; } } } return p; }}ans;struct Tpoint{ double x,y,z; friend Tpoint operator + (const Tpoint &a, const Tpoint &b) {return Tpoint(a.x+b.x, a.y+b.y, a.z+b.z);} friend Tpoint operator - (const Tpoint &a, const Tpoint &b) {return Tpoint(a.x-b.x, a.y-b.y, a.z-b.z);} friend Tpoint operator * (const Tpoint &a, double k) {return Tpoint(a.x*k, a.y*k, a.z*k);} friend Tpoint operator / (const Tpoint &a, double k) {return Tpoint(a.x/k, a.y/k, a.z/k);} friend double operator * (const Tpoint &a, const Tpoint &b) {return a.x*b.x+a.y*b.y+a.z*b.z;} friend Tpoint operator ^ (const Tpoint &a, const Tpoint &b) {return Tpoint(a.y*b.z-a.z*b.y, a.z*b.x-a.x*b.z, a.x*b.y-a.y*b.x);} double len() {return sqrt((*this)*(*this));} Tpoint (double x = 0,double y = 0,double z = 0):x(x),y(y),z(z){} void read(){ scanf("%lf%lf%lf",&x,&y,&z); } void print(){ printf("%.2f %.2f %.2f\n",x,y,z); }};Tmatrix trans(double addx,double addy,double addz){ Tmatrix m; m.init(); for(int i = 0 ; i < 4; i++) m.mat[i][i] = 1; m.mat[0][3] = addx;m.mat[1][3] = addy;m.mat[2][3] = addz; return m;}Tmatrix scal(double tx,double ty,double tz){ Tmatrix m; m.init(); m.mat[0][0] = tx;m.mat[1][1] = ty;m.mat[2][2] = tz;m.mat[3][3] = 1; return m;}Tmatrix rot(Tpoint p,Tpoint vv,double t){ Tmatrix m; Tpoint tmp = vv/vv.len(); //cout <<vv.x<<" "<<vv.y<<" "<<vv.z<<endl; double u = tmp.x; double v = tmp.y; double w = tmp.z; double a = p.x; double b = p.y; double c = p.z; double mak[4][4] = { {u*u+(v*v+w*w)*cos(t), u*v*(1-cos(t))-w*sin(t), u*w*(1-cos(t))+v*sin(t), (a*(v*v+w*w)-u*(b*v+c*w))*(1-cos(t))+(b*w-c*v)*sin(t)}, {u*v*(1-cos(t))+w*sin(t), v*v+(u*u+w*w)*cos(t), v*w*(1-cos(t))-u*sin(t), (b*(u*u+w*w)-v*(a*u+c*w))*(1-cos(t))+(c*u-a*w)*sin(t)}, {u*w*(1-cos(t))-v*sin(t), v*w*(1-cos(t))+u*sin(t), w*w+(u*u+v*v)*cos(t), (c*(u*u+v*v)-w*(a*u+b*v))*(1-cos(t))+(a*v-b*u)*sin(t)}, { 0.0, 0.0, 0.0, 1.0} }; for(int i = 0 ; i < 4; i++) for(int j = 0 ; j < 4; j++) m.mat[i][j] = mak[i][j]; return m;}int n;char s[3];void init(){ scanf("%d",&n); ans.init(); for(int i = 0 ; i < 4 ; i++) ans.mat[i][i] = 1; for(int i = 0 ; i < n ; i++){ scanf("%s",s); //printf("%s\n",s); Tpoint a; a.read(); //a.print(); if(s[0] == 'T'){ ans = trans(a.x,a.y,a.z).mul(ans); } else if(s[0] == 'S'){ ans = scal(a.x,a.y,a.z).mul(ans); } else{ double ang; scanf("%lf",&ang); ang = ang*PI/180; ans = rot(Tpoint(0,0,0),a,ang).mul(ans); } //cout <<ans.mat[0][0]<<" "<<ans.mat[0][1] <<" "<<ans.mat[0][2]<<" "<<ans.mat[0][3]<<endl; //cout <<ans.mat[1][0]<<" "<<ans.mat[1][1] <<" "<<ans.mat[1][2]<<" "<<ans.mat[1][3]<<endl; //cout <<ans.mat[2][0]<<" "<<ans.mat[2][1] <<" "<<ans.mat[2][2]<<" "<<ans.mat[2][3]<<endl; //cout <<ans.mat[3][0]<<" "<<ans.mat[3][1] <<" "<<ans.mat[3][2]<<" "<<ans.mat[3][3]<<endl; }}void sov(){ scanf("%d",&n); for(int i = 0 ; i < n ; i++){ Tpoint a,b; a.read(); //cout <<a.x<<" "<<a.y<<" "<<a.z<<endl; b.x = a.x*ans.mat[0][0]+ans.mat[0][1]*a.y+ans.mat[0][2]*a.z+ans.mat[0][3]; b.y = a.x*ans.mat[1][0]+ans.mat[1][1]*a.y+ans.mat[1][2]*a.z+ans.mat[1][3]; b.z = a.x*ans.mat[2][0]+ans.mat[2][1]*a.y+ans.mat[2][2]*a.z+ans.mat[2][3]; b.print(); }}int main(){ init(); sov();}/*1R 0.0 0.0 1.0 2.032.0 3.0 4.0*/
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