HDU2057 A + B Again

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

 

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

 

Output

For each test case,print the sum of A and B in hexadecimal in one line.

 

Sample Input

+A -A+1A 121A -9-1A -121A -AA

 

Sample Output

02C11-2C-90

 

Author

linle

 

Source

校庆杯Warm Up

HDU2057#include<iostream>#include<cstdio>#include<cstring>#include<cmath>#include<cstdlib>using namespace std;int main(){ long long  a,b; while(~scanf("%llX%llX",&a,&b)){if(a+b<0) {a=-a;b=-b;cout<<"-";}printf("%llX\n",a+b); } return 0;}

("%X",a)表示16进制处理a，x时是小写