hdu2057 A + B Again

A + B Again

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 25617    Accepted Submission(s): 10406

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

 

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

 

Output

For each test case,print the sum of A and B in hexadecimal in one line.

 

Sample Input

+A -A+1A 121A -9-1A -121A -AA

 

Sample Output

02C11-2C-90

 

这道题本来是一次过的，思路完全正确，但是在输出格式那里，我本来是

                if(a+b<0)printf("-%llx\n",-(a+b));else printf("%llx\n",a+b);

按十六进制输出，我这里用的是小写‘x’，但是就是ac不了，改成大写的‘X’就可以了，搞不懂

#include<cstdio>int main(){long long a,b;while(scanf("%llX %llX",&a,&b)!=EOF){if(a+b<0)printf("-%llX\n",-(a+b));else printf("%llX\n",a+b);}return 0;}