2016微软探星夏令营在线技术笔试-#1342 : Full Binary Tree Picture

来源：互联网发布：excel2016数据验证编辑：程序博客网时间：2024/06/14 00:46

http://hihocoder.com/problemset/problem/1342

题意理解：找规律，N=1，2是特殊的，之后的就有规律了：y坐标最下一层是2，4，2，4的差，最后就是差6， 12， 24.。。。x左边最下差2，之后是3，6，12.。。。一行一行的算，算某一行的时候，写出来最左边为第一项的等差数列通项，然后用f（y2） - f（y1 - 1）来算

急转弯：有点麻烦

算法：无

数据结构：无

from __future__ import print_function##'guilv'__author__ = 'hjkruclion'import sysimport mathdef read_int():    return list(map(int, sys.stdin.readline().split()))maxn = 50x = [[] for i in range(maxn)]y = [0 for i in range(maxn)]delt_y = [0 for i in range(maxn)]N, M = read_int()t = 3if N >= 2:    delt_y[N - 2] = 2for i in reversed(range(0, N - 2)):    delt_y[i] = t    t *= 2y[0] = 0for i in range(1, N):    y[i] = y[i - 1] + delt_y[i - 1]for _ in range(M):    x1, y1, x2, y2 = read_int()    x1, y1 = y1, x1    x2, y2 = y2, x2    if N == 1:        if x1 <= 0 and y1 <= 0 and x2 >= 0 and y2 >= 0:            print(1)        else:            print(0)    elif N == 2:        ans = 0        if x1 <= 0 and y1 <= 0 and x2 >= 0 and y2 >= 0:            ans += 1        if y1 <= 2 and y2 >= 2:            t1 = min(2, max(0, ((x1 - 1) + 6) // 4))            t2 = min(2, max(0, (x2 + 6) // 4))            ans += t2 - t1        print(ans)    else:        ans = 0        if y1 <= y[N - 1] and y2 >= y[N - 1]:            t1 = min(2 ** (N - 2), max(0, ((x1 - 1) + 5 + 3 * (2 ** (N - 2))) // 6))            t2 = min(2 ** (N - 2), max(0, (x2 + 5 + 3 * (2 ** (N - 2))) // 6))            ans += t2 - t1            t1 = min(2 ** (N - 2), max(0, ((x1 - 1) + 1 + 3 * (2 ** (N - 2))) // 6))            t2 = min(2 ** (N - 2), max(0, (x2 + 1 + 3 * (2 ** (N - 2))) // 6))            ans += t2 - t1        # print(ans)        t = 6        for i in reversed(range(1, N - 1)):            t1 = min(2 ** i, max(0, ((x1 - 1) + t // 2 + 2 ** (i - 1) * t) // t))            t2 = min(2 ** i, max(0, (x2 + t // 2 + 2 ** (i - 1) * t) // t))            if y1 <= y[i] and y2 >= y[i]:                ans += t2 - t1            t *= 2        if x1 <= 0 and y1 <= 0 and x2 >= 0 and y2 >= 0:            ans += 1        # for i in range(0, N):        #     print(i, y[i])        print(ans)

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