【20170926】C语言每日一练

【程序4】
题目：输入某年某月某日，判断这一天是这一年的第几天？

#include <stdio.h>int main(int argc, char* argv[]){    int year,month,date;    int sum = 0;    int month2;    printf("请输入年份：");    scanf("%d",&year);    printf("请输入月份：");    scanf("%d",&month);    printf("请输入日期：");    scanf("%d",&date);    if((year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0)))    {        month2 = 29;    }    else    {        month2 = 28;    }    switch(month)    {        case 1:            sum = date;            break;        case 3:            sum = 31 + month2 + date;            break;        case 4:            sum = 62 + month2 + date;            break;        case 5:            sum = 92 + month2 + date;            break;        case 6:            sum = 123 + month2 + date;            break;        case 7:            sum = 153 + month2 + date;            break;        case 8:            sum = 184 + month2 + date;            break;        case 9:            sum = 215 + month2 + date;            break;        case 10:            sum = 245 + month2 + date;            break;        case 11:            sum = 276 + month2 + date;            break;        case 12:            sum = 286 + month2 + date;            break;    }    printf("The sum is %d",sum);}

运行结果：

【程序5】
题目：输入三个整数x,y,z，请把这三个数由小到大输出。

#include <stdio.h>void main(void){    int x, y, z;    printf("请输入x：");    scanf("%d", &x);    printf("请输入y：");    scanf("%d", &y);    printf("请输入z：");    scanf("%d", &z);    int min = x;    if (x > y)    {        min = y;        y = x;        x = min;    }    if (x > z)    {        min = x;        x = z;        z = min;    }    if (y > z)    {        min = z;        z = y;        y = min;    }    printf("The sort queue is %d,%d,%d\n", x, y, z);}

运行结果：

【程序六】
用*输出C的图案

#include <stdio.h>void main(void){    printf("    ****\n");    printf("  *\n");    printf(" *\n");    printf(" *\n");    printf("  *\n");    printf("    ****\n");}

**【程序8】
题目：输出9*9口诀。**

#include <stdio.h>int main(int argc, char* argv[]){    int i,j;    int count = 0;    for(i = 1;i <= 9;i++)    {        for(j = 1; j <= 9; j++)        {            printf("%d\t",i*j);            count++;            if(count % 9==0)            {                printf("\n");            }        }    } }

运行结果：