hdu1163 Eddy's digital Roots

来源:互联网 发布:linux nodejs运行 编辑:程序博客网 时间:2024/05/21 09:00
Problem Description
The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the process is repeated. This is continued as long as necessary to obtain a single digit.

For example, consider the positive integer 24. Adding the 2 and the 4 yields a value of 6. Since 6 is a single digit, 6 is the digital root of 24. Now consider the positive integer 39. Adding the 3 and the 9 yields 12. Since 12 is not a single digit, the process must be repeated. Adding the 1 and the 2 yeilds 3, a single digit and also the digital root of 39.

The Eddy's easy problem is that : give you the n,want you to find the n^n's digital Roots.
 

Input
The input file will contain a list of positive integers n, one per line. The end of the input will be indicated by an integer value of zero. Notice:For each integer in the input n(n<10000).
 

Output
Output n^n's digital root on a separate line of the output.
 

Sample Input
240
 

Sample Output
44
 

Author
eddy

C语言AC代码
#include<stdio.h>int main(){    int n;    while(scanf("%d",&n)&&n)    {        int i,temp;        temp=n;        for(i=1;i<n;i++)            temp=temp*n%9;        if(temp!=0)            printf("%d\n",temp);        else            printf("9\n");    }    return 0;}
思路:九余数定理,注意当余数为0时就是9。

九余数定理:一个数对9取余后的值为九余数,一个数的各位数字相加之和并且小于10的数字称为这个数字的九余数,
有兴趣可以再学习一下同余定理。