python3绘制超立方体

利用Python3中turtle的绘制超立方体。

绘图思路：

1）求出边长100的超立方体的点坐标；

      以竖直线为依据，将点分为上下两组：

      a为上边点列表，b为下边点列表：

   a = [[120.71, 50], [50, 120.71], [-50, 120.71], [-120.71, 50], [-50, -20.71], [50, -20.71], [20.71, 50],[-20.71, 50]]   b = [[120.71, -50], [50, 20.71], [-50, 20.71], [-120.71, -50], [-50, -120.71], [50, -120.71], [20.71, -50],[-20.71, -50]]

2）编写绘制直线函数；

3）编写主程序：绘制点，绘制六角形直线，绘制竖直直线，绘制斜线

代码片段如下，可能不是最简洁的，如有好的建议，请不吝指正。

import turtle# 创建绘制直线函数def drawLine(p1, p2, size=3, color="black"):    turtle.penup()    turtle.goto(p1)    turtle.pensize(size)    turtle.pencolor(color)    turtle.pendown()    turtle.goto(p2)def main():    # 求取点后，将超立方体点分为上下两个部分，两个列表    a = [[120.71, 50], [50, 120.71], [-50, 120.71], [-120.71, 50], [-50, -20.71], [50, -20.71], [20.71, 50],         [-20.71, 50]]    b = [[120.71, -50], [50, 20.71], [-50, 20.71], [-120.71, -50], [-50, -120.71], [50, -120.71], [20.71, -50],         [-20.71, -50]]        # 绘制点    turtle.pencolor("red")    turtle.penup()    for i in range(len(a)):        turtle.goto(a[i])        turtle.down()        turtle.dot(10, "red")        turtle.penup()    for i in range(len(b)):        turtle.goto(b[i])        turtle.down()        turtle.dot(10, "red")        turtle.penup()            # 绘制六边形直线    for i in range(6):        if i <= 4:            drawLine(a[i], a[i + 1])            drawLine(b[i], b[i + 1])        else:            drawLine(a[i], a[0])            drawLine(b[i], b[0])    # 绘制竖直线    for i in range(len(a)):        drawLine(a[i], b[i])        # 绘制斜线    drawLine(a[6], a[0])    drawLine(a[6], a[2])    drawLine(a[6], a[4])    drawLine(a[7], a[1])    drawLine(a[7], a[3])    drawLine(a[7], a[5])    drawLine(b[6], b[0])    drawLine(b[6], b[2])    drawLine(b[6], b[4])    drawLine(b[7], b[1])    drawLine(b[7], b[3])    drawLine(b[7], b[5])    turtle.done()if __name__ == '__main__':    main()    pass