HDOJ 2100 Lovekey

HDACM2100
此题别被题目忽悠去把输入的二十六进制数转换成十进制然后去计算，然后把十进制转换成二十六进制。如果非要转换那就得调用大数的方法去做。

import java.util.Scanner;public class Main{    public static void main(String[] args) {        Scanner sc = new Scanner(System.in);        while (sc.hasNext()) {            String a = sc.next();            String b = sc.next();            char[] A = a.toCharArray();            char[] B = b.toCharArray();            char[] C = twentySixAdd(A, B);            boolean boo = true;            for (char d : C) {                if (boo&&d=='A'||d=='\0') {                    continue;                }                System.out.print(d);                boo = false;            }            System.out.println();        }    }    public static char[] twentySixAdd(char[] a,char[] b){        char[] c = new char[(a.length>b.length?a.length:b.length)+1];        char m = 0;        for (int i = c.length-1; i>0; i--) {            if (c[i]=='\0') {                c[i] = 'A';            }            if (i>c.length-(a.length<b.length?a.length:b.length)-1) {                char s = (char)(c[i]+a[i-(c.length-a.length)]+b[i-(c.length-b.length)]-'A'-'A');                if (s>'Z') {                    c[i] = (char) (s-'Z'-1+'A');                    c[i-1] = 'B';                }else{                    c[i] = s;                }            }else {                if (a.length>b.length) {                    char s = (char) (c[i]+a[i-(c.length-a.length)]-'A');                    if (s>'Z') {                        c[i] = (char) (s-'Z'-1+'A');                        c[i-1] = 'B';                    }else{                        c[i] = s;                    }                    }else {                    char s = (char) (c[i]+b[i-(c.length-b.length)]-'A');                    if (s>'Z') {                        c[i] = (char) (s-'Z'-1+'A');                        c[i-1] = 'B';                    }else{                        c[i] = s;                    }                }            }        }        return c;    }}