LeetCode 2 Add Two Number

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8

摘要： 翻译： 给你两个表示两个非负数字的链表。数字以相反的顺序存储，其节点包含单个数字。将这两个数字相加并将其作为一个链表返回。 输入: (2 -> 4 -> 3) + (5 -> 6 -> 4) 输出: 7 -> 0 -> 8

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C++:

/** * Definition for singly-linked list. * struct ListNode { *     int val; *     ListNode *next; *     ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution{ public:      ListNode *addTwoNumbers(ListNode* l1, ListNode* l2){      int sum = 0;      ListNode *listNode = new ListNode(0);      ListNode *p1=l1, *p2=l2, *p3=listNode;      while(p1!=NULL||p2!=NULL)      {      if(p1!=NULL)      {          sum+=p1->val;          p1=p1->next;      }      if(p2!=NULL)      {          sum+=p2->val;          p2=p2->next;      }      p3->next=new ListNode(sum%10);      p3=p3->next;      sum=sum/10;      }      if(sum==1)      {     p3->next=new ListNode(1);      }      return listNode->next;      } };