实时求一段0、1序列1的比例

#define  MIN(a,b) ((a) < (b) ? (a) : (b))#define FLAG_BUFF_LEN_BYTE 125#define FLAG_BUFF_LEN_BIT ( FLAG_BUFF_LEN_BYTE * 8)#define LONG_SMOOTH_NUM 1000unsigned short short_count; ///< Number of  shortsunsigned char buff[FLAG_BUFF_LEN_BYTE]; ///< The flag buff, save as bitint pre_count;int index_byte; ///< The index by byteunsigned int index_bit;  ///< The index by bitfloat ratio_short_mean; ///< The short ratiofloat ratio_long_smooth;    ///< The long ratioshort_count = 0;memset(buff, 0, sizeof(buff));pre_count = 0;index_byte = 0;index_bit = 1;ratio_short_mean = 0;ratio_long_smooth = 0;if (flag){    count += (1 - ((buff[index_byte] & (unsigned char)index_bit) != 0 ? 1 : 0)); // if bit is 0, plus 1;else do nothing    buff[index_byte] |= index_bit; // flush new value}else{    count -= (1 - ((buff[index_byte] & (unsigned char)index_bit) == 0 ? 1 : 0)); // if bit is 1, minus 1;else do nothing    buff[index_byte] &= (~index_bit); // flush new value}index_bit <<= 1;if (index_bit > 128){    index_bit = 1;    index_byte = (index_byte + 1) % FLAG_BUFF_LEN_BYTE;}if (pre_count < 1073741824){    pre_count++;}ratio_short_mean = (float)short_count / MIN(pre_count, FLAG_BUFF_LEN_BIT);ratio_long_smooth = ((pre_count - 1) * ratio_long_smooth + flag) / MIN(pre_count, LONG_SMOOTH_NUM);