[CodeForces

来源:互联网 发布:linux mint 中文 编辑:程序博客网 时间:2024/05/17 06:03

Link:http://codeforces.com/problemset/problem/652/B


B. z-sort
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

A student of z-school found a kind of sorting called z-sort. The array a with n elements are z-sorted if two conditions hold:

  1. ai ≥ ai - 1 for all even i,
  2. ai ≤ ai - 1 for all odd i > 1.

For example the arrays [1,2,1,2] and [1,1,1,1] are z-sorted while the array [1,2,3,4] isn’t z-sorted.

Can you make the array z-sorted?

Input

The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of elements in the array a.

The second line contains n integers ai (1 ≤ ai ≤ 109) — the elements of the array a.

Output

If it's possible to make the array a z-sorted print n space separated integers ai — the elements after z-sort. Otherwise print the only word "Impossible".

Examples
input
41 2 2 1
output
1 2 1 2
input
51 3 2 2 5
output
1 5 2 3 2

Code:

#include<cstdio>#include<cstdlib>#include<cmath>#include<cstring>#include<algorithm>#include<iostream>#include<queue>#include<stack>using namespace std;int a[1005],b[1005];int main(){int n;while(~scanf("%d",&n)){for(int i=1;i<=n;i++)scanf("%d",&a[i]);int k=1;sort(a+1,a+1+n);for(int i=1;i<=n;i+=2)b[i]=a[k++];  //所有奇数位上的数都小于上一个数for(int i=2;i<=n;i+=2)b[i]=a[k++];  //所有偶数位上的数都大于上一个数for(int i=1;i<=n;i++)printf("%d%c",b[i],i==n? '\n':' ');}return 0;}


原创粉丝点击