[LeetCode]64. Minimum Path Sum
来源:互联网 发布:下载输入法软件 编辑:程序博客网 时间:2024/06/16 06:52
Minimum Path Sum
- 问题描述
- 代码
- 代码分析
问题描述
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
Example 1:
[[1,3,1],
[1,5,1],
[4,2,1]]
Given the above grid map, return 7. Because the path 1→3→1→1→1 minimizes the sum.
代码
class Solution {public: int a[500][500]={0};//到a[i][j]的最短距离 int minPathSum(vector<vector<int>>& grid) { int w = grid.size(); int h = grid[0].size(); a[0][0] = grid[0][0]; for(int i = 0; i<w;++i) for(int j = 0; j<h;++j) if(!(i == 0 && j == 0)) if( i == 0) a[i][j] = a[i][j-1] + grid[i][j]; else if(j == 0) a[i][j] = a[i-1][j] + grid[i][j]; else a[i][j] = min(a[i-1][j],a[i][j-1])+grid[i][j]; return a[w-1][h-1]; }};
代码分析
很基础的动态规划题目。
到某点的距离最短,则在所有前一步里取得最短的再加上当前value。
即可以得到递推公式
f(i,j) = min(f(i-1,j),f(i,j-1))+grid(i,j)
题目中即为上方一格和左方一格中选取较小的。
注意当在第一行和第一列的时候要考虑边界情况
阅读全文
0 0
- [LeetCode]64.Minimum Path Sum
- LeetCode --- 64. Minimum Path Sum
- LeetCode 64.Minimum Path Sum
- [Leetcode] 64. Minimum Path Sum
- [leetcode] 64.Minimum Path Sum
- [leetcode] 64.Minimum Path Sum
- LeetCode 64. Minimum Path Sum
- 64. Minimum Path Sum LeetCode
- [LeetCode]64. Minimum Path Sum
- leetcode 64. Minimum Path Sum
- [leetcode] 64. Minimum Path Sum
- LeetCode 64. Minimum Path Sum
- LeetCode *** 64. Minimum Path Sum
- leetcode 64. Minimum Path Sum
- 【leetcode】64. Minimum Path Sum
- Leetcode:64. Minimum Path Sum
- LeetCode-64.Minimum Path Sum
- LeetCode 64. Minimum Path Sum
- 机器学习综述
- LINUX学习笔记(八)
- lambda表达式
- JavaScript类型转换的特殊用法
- 数据结构--基本概念
- [LeetCode]64. Minimum Path Sum
- 2017年10月23日提高组T2 灵知的太阳信仰
- CentOS下安装配置LAMP(Linux+Apache+MySQL+PHP)
- GYM
- Oracle数据库的union与intersect
- Zigzag Iterator ii
- Java内存分配详解(堆内存、栈内存、常量池)
- NOJ(1575)-回溯算法-图的m着色问题
- bzoj 2438: [中山市选2011]杀人游戏 强连通分量