Google地图百度地图GPS经纬度偏移转换(JAVA)

不多说，直接代码，Java版

主要就是Google地图，百度地图，GPS经纬度偏移转换

GCJ-02转换BD-09,Google地图经纬度转百度地图经纬度
BD-09转换GCJ-02,百度转google
WGS-84 到 GCJ-02 的转换（即 GPS 加偏）

/** * 用于构造地图中的坐标点 * @author lw * **/public class Point {private double lat;// 纬度private double lng;// 经度public Point() {}public Point(double lng, double lat) {this.lng = lng;this.lat = lat;}@Overridepublic boolean equals(Object obj) {if (obj instanceof Point) {Point bmapPoint = (Point) obj;return (bmapPoint.getLng() == lng && bmapPoint.getLat() == lat) ? true : false;} else {return false;}}public double getLat() {return lat;}public void setLat(double lat) {this.lat = lat;}public double getLng() {return lng;}public void setLng(double lng) {this.lng = lng;}@Overridepublic String toString() {return "Point [lat=" + lat + ", lng=" + lng + "]";}}

/** * 地图坐标转换 google,baidu,gps * @author lw * @Time 2015年4月16日18:19:16 *  * */public class CoordinateConversion {private static final double x_pi = 3.14159265358979324 * 3000.0 / 180.0;private static final double pi = 3.14159265358979324;private static final double a = 6378245.0;private static final double ee = 0.00669342162296594323;/** * gg_lat 纬度 * gg_lon 经度 * GCJ-02转换BD-09 * Google地图经纬度转百度地图经纬度 * */public static Point google_bd_encrypt(double gg_lat, double gg_lon){Point point=new Point();double x = gg_lon, y = gg_lat;double z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * x_pi);double theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * x_pi); double bd_lon = z * Math.cos(theta) + 0.0065;double bd_lat = z * Math.sin(theta) + 0.006;point.setLat(bd_lat);point.setLng(bd_lon);return point;}/** * wgLat 纬度 * wgLon 经度 * BD-09转换GCJ-02 * 百度转google * */public static Point bd_google_encrypt(double bd_lat, double bd_lon){Point point=new Point();    double x = bd_lon - 0.0065, y = bd_lat - 0.006;      double z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi);      double theta =Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi);      double gg_lon = z * Math.cos(theta);      double gg_lat = z * Math.sin(theta);      point.setLat(gg_lat);    point.setLng(gg_lon);    return point;}/** * wgLat 纬度 * wgLon 经度 * WGS-84 到 GCJ-02 的转换（即 GPS 加偏） * */public static Point wgs_gcj_encrypts(double wgLat, double wgLon) {Point point=new Point();if (outOfChina(wgLat, wgLon)) {point.setLat(wgLat);point.setLng(wgLon);return point;}double dLat = transformLat(wgLon - 105.0, wgLat - 35.0);double dLon = transformLon(wgLon - 105.0, wgLat - 35.0);double radLat = wgLat / 180.0 * pi;double magic = Math.sin(radLat);magic = 1 - ee * magic * magic;double sqrtMagic = Math.sqrt(magic);dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);double lat = wgLat + dLat;double lon = wgLon + dLon;point.setLat(lat);point.setLng(lon);return point;}public static void transform(double wgLat, double wgLon, double[] latlng) {if (outOfChina(wgLat, wgLon)) {latlng[0] = wgLat;latlng[1] = wgLon;return;}double dLat = transformLat(wgLon - 105.0, wgLat - 35.0);double dLon = transformLon(wgLon - 105.0, wgLat - 35.0);double radLat = wgLat / 180.0 * pi;double magic = Math.sin(radLat);magic = 1 - ee * magic * magic;double sqrtMagic = Math.sqrt(magic);dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);latlng[0] = wgLat + dLat;latlng[1] = wgLon + dLon;}private static boolean outOfChina(double lat, double lon) {if (lon < 72.004 || lon > 137.8347)return true;if (lat < 0.8293 || lat > 55.8271)return true;return false;}private static double transformLat(double x, double y) {double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.sqrt(Math.abs(x));ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;ret += (20.0 * Math.sin(y * pi) + 40.0 * Math.sin(y / 3.0 * pi)) * 2.0 / 3.0;ret += (160.0 * Math.sin(y / 12.0 * pi) + 320 * Math.sin(y * pi / 30.0)) * 2.0 / 3.0;return ret;}private static double transformLon(double x, double y) {double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.sqrt(Math.abs(x));ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;ret += (20.0 * Math.sin(x * pi) + 40.0 * Math.sin(x / 3.0 * pi)) * 2.0 / 3.0;ret += (150.0 * Math.sin(x / 12.0 * pi) + 300.0 * Math.sin(x / 30.0 * pi)) * 2.0 / 3.0;return ret;}}

声明：算法不是出自本人，以整理验证通过