POJ系列——java

入门

POJ1003

懒得翻译，题目大概意思

求1/2+1/3+…1/(n+1)>=c时的最小n值。（0.00<=c<=5.20）

代码：

public static void main(String[] args) {

    Scanner in = new Scanner(System.in);    while (in.hasNext()){        double c = in.nextDouble();        double sum = 0.0;        int n = 1;        if (c==0) {            return;        }        do {            n++;            sum = sum + 1.0 / n;        } while (sum<c);            System.out.println((n-1)+" card(s)");    }}