如何把数字金额转换成中文大写

问题：要求把万亿级别内的浮点数转换成中文大写，例如把数字1112221000060.254400转换成：壹万壹仟壹佰贰拾贰亿贰仟壹佰万零陆拾元零贰角伍分

 

分析：关键是先把double类型转换成char字符串，然后逐个字符进行转换。区分3中情况：字符为0，字符不为0，字符为0且后继所有字符为0。

 

numberString.h头文件：

#include <stdio.h>#include <stdlib.h>#include <string.h>#define MAXSTRINGLENGTH 200#define SUCCESS 0#define ERROR -1//定义用来存储转换后存储中文大写的字符串char str_ZH[MAXSTRINGLENGTH];//中文数字，汉字为双字节编码，再加上'/0'结束符，所以宽度为3char zh[11][3] = {"零","壹","贰","叁","肆","伍","陆","柒","捌","玖","拾"};//中文数字单位，仅支持到万亿char unit[15][3] = {"万","仟","佰","拾","亿","仟","佰","拾","万","仟","佰","拾","元","角","分"};//存储数字转换成字符串后存储的变量，因为只需要支持到万亿级别，加上两位小数和结束的'/0'，一共长度为16char numStr[16];

 

main文件：

#include "numberString.h"//把小数金额转换成中文大写int convert(double num){int i;int strLen;int zeroFlag = 0;char temp[20];printf("the number is [%f]/n", num);str_ZH[0] = '/0';//精确到小数点后2位，转换成分sprintf(numStr, "%.0f", 100*num);strLen = strlen(numStr);for (i=0; i<strLen; i++){strcpy(temp, numStr + i);if (0 == atoi(temp)){zeroFlag = 2;break;}if ('0' != numStr[i]){if (1 == zeroFlag){strcat(str_ZH, zh[0]);zeroFlag = 0;}strcat(str_ZH, zh[numStr[i] - '0']);strcat(str_ZH, unit[15 - (strLen - i)]);}else{ zeroFlag = 1;if (11 == strLen - i){strcat(str_ZH, "亿");}if (7 == strLen - i){strcat(str_ZH, "万");}if (3 == strLen - i){strcat(str_ZH, "元");}}}if (2 == zeroFlag){if (11 <= strLen - i && 16 > strLen - i){strcat(str_ZH, "亿");}else if (7 <= strLen - i && 10 > strLen - i){strcat(str_ZH, "万");}if (3 <= strLen - i){strcat(str_ZH, "元");}strcat(str_ZH, "整");}return SUCCESS;}int main(){ convert(1234560.253);printf("after convert is: %s/n", str_ZH); convert(1000060.2543);printf("after convert is: %s/n", str_ZH);convert(1112221000060.2543);printf("after convert is: %s/n", str_ZH);convert(1000000.2543);printf("after convert is: %s/n", str_ZH); convert(1030560.00);printf("after convert is: %s/n", str_ZH);convert(10000000.00);printf("after convert is: %s/n", str_ZH);}