线程同步与线程调度初探_发牌功能

来源：互联网发布：澳洲排油丸知乎编辑：程序博客网时间：2024/06/15 20:32

问题：一个发牌线程和四个取牌线程间的两种同步问题

首先确定一个缓存区，去放一张牌，并设置一个信号量

class CardBuffer {private int value;private boolean isEmpty=true;private int order=0;private int number;CardBuffer(int number){ this.number=number;}synchronized void put(int i){while(!this.isEmpty)try{ this.wait();}catch(InterruptedException ex){}this.value=i;this.isEmpty=false;this.notifyAll();}synchronized int get(int order){ //同步锁while(this.isEmpty||(this.order!=order))try{this.wait();}catch(InterruptedException ex){}this.isEmpty=true;this.notifyAll();this.order=(this.order+1)%this.number;return this.value;}}

然后确定一个发牌线程，每一发出一张牌

class SendCardThread extends Thread{private CardBuffer cardbuffer;private int cardMax;private int number;public SendCardThread(CardBuffer cardbuffer,int cardMax,int number){this.cardbuffer=cardbuffer;this.cardMax=cardMax;this.number=number;this.setPriority(Thread.MAX_PRIORITY);}public void run(){for(int i=1;i<this.cardMax;i++){this.cardbuffer.put(i);}for(int i=1;i<this.number;i++)this.cardbuffer.put(-1);}}

确定取牌线程，要考虑到多种情况

class ReceiveCardJFrame extends JFrame implements Runnable{private CardBuffer cardbuffer;private JTextArea text;private int order;public ReceiveCardJFrame(CardBuffer cardbuffer,int order,String title,int x,int y){super(title);this.setBounds(x, y, 250, 100);this.setDefaultCloseOperation(EXIT_ON_CLOSE);this.order=order;this.cardbuffer=cardbuffer;this.text=new JTextArea();this.getContentPane().add(this.text);this.text.setLineWrap(true);this.text.setEditable(false);this.text.setFont(new Font("Arial",Font.PLAIN,20));this.setVisible(true);new Thread(this).start();}public void run(){while(true){int value=this.cardbuffer.get(this.order);if(value==-1)return;this.text.append(String.format("%4d",value));try{Thread.sleep(1000);}catch(InterruptedException ex){}}}}

程序结果如图

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