py2中存储的pickle和py3中pickle无法读取的兼容性问题解决方案

来源：互联网发布：编程菱形编辑：程序博客网时间：2024/06/09 10:37

问题描述

在py2.7当中，用以下语句将变量存储到pickle当中

with open('../dataset/m_7800/rf_preds.pickle', 'wb') as f:    pickle.dump(rf_preds, f)

这个时候，用py3.6中的pickle取获取存储好的变量

with open('../dataset/m_7800/rf_preds.pickle', 'rb') as f:    rf_preds = pickle.load(f)

会报错

---------------------------------------------------------------------------UnicodeDecodeError                        Traceback (most recent call last)<ipython-input-21-8326d2e71e16> in <module>()      1 with open('../dataset/m_7800/rf_preds.pickle', 'rb') as f:----> 2     rf_preds = pickle.load(f)UnicodeDecodeError: 'ascii' codec can't decode byte 0xb1 in position 8: ordinal not in range(128)

解决方案

在py3.6的load的过程当中加入encoding=’latin1’即可。

with open('../dataset/m_7800/rf_preds.pickle', 'rb') as f:    rf_preds = pickle.load(f, encoding='latin1')

如果仍旧不行，可以在py2.7存储的时候加入protocol=2，再用上面的方式进行load操作，如下

with open('../dataset/m_7800/rf_preds.pickle', 'wb') as f:    pickle.dump(rf_preds, f, protocol=2)

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