Java随机生成批量Ip

来源：互联网发布：易语言数据统计分析编辑：程序博客网时间：2024/05/16 15:56

近期根据项目需求在网上找找了再根据自己需求，感觉很实用，所以贴出来共享。

随机获取国内ip地址；

public static String getRandomIp() {// ip范围int[][] range = { { 607649792, 608174079 }, // 36.56.0.0-36.63.255.255{ 1038614528, 1039007743 }, // 61.232.0.0-61.237.255.255{ 1783627776, 1784676351 }, // 106.80.0.0-106.95.255.255{ 2035023872, 2035154943 }, // 121.76.0.0-121.77.255.255{ 2078801920, 2079064063 }, // 123.232.0.0-123.235.255.255{ -1950089216, -1948778497 }, // 139.196.0.0-139.215.255.255{ -1425539072, -1425014785 }, // 171.8.0.0-171.15.255.255{ -1236271104, -1235419137 }, // 182.80.0.0-182.92.255.255{ -770113536, -768606209 }, // 210.25.0.0-210.47.255.255{ -569376768, -564133889 }, // 222.16.0.0-222.95.255.255};Random rdint = new Random();int index = rdint.nextInt(10);String ip = num2ip(range[index][0] + new Random().nextInt(range[index][1] - range[index][0]));return ip;}/* * 将十进制转换成IP地址 */public static String num2ip(int ip) {int[] b = new int[4];String x = "";b[0] = (int) ((ip >> 24) & 0xff);b[1] = (int) ((ip >> 16) & 0xff);b[2] = (int) ((ip >> 8) & 0xff);b[3] = (int) (ip & 0xff);x = Integer.toString(b[0]) + "." + Integer.toString(b[1]) + "." + Integer.toString(b[2]) + "." + Integer.toString(b[3]);return x;}public static void main(String[] args) {int count = 100000;for (int i = 0; i < count; i++) {String randomIp = getRandomIp();System.err.println(randomIp);}}

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