生成随机的IP地址

来源：互联网发布：mac大型单机游戏下载编辑：程序博客网时间：2024/06/04 19:07
public class IpUtil {    public static void main(String[] args) {        String randomIp = getRandomIp();        System.out.println(randomIp);    }    public static String getRandomIp(){        //ip范围        int[][] range = {{607649792,608174079},//36.56.0.0-36.63.255.255                         {1038614528,1039007743},//61.232.0.0-61.237.255.255                         {1783627776,1784676351},//106.80.0.0-106.95.255.255                         {2035023872,2035154943},//121.76.0.0-121.77.255.255                         {2078801920,2079064063},//123.232.0.0-123.235.255.255                         {-1950089216,-1948778497},//139.196.0.0-139.215.255.255                         {-1425539072,-1425014785},//171.8.0.0-171.15.255.255                         {-1236271104,-1235419137},//182.80.0.0-182.92.255.255                         {-770113536,-768606209},//210.25.0.0-210.47.255.255                         {-569376768,-564133889}, //222.16.0.0-222.95.255.255        };        Random rdint = new Random();        int index = rdint.nextInt(10);        String ip = num2ip(range[index][0]+new Random().nextInt(range[index][1]-range[index][0]));        return ip;    }     public static String num2ip(int ip) {            int [] b=new int[4] ;            String x = "";            b[0] = (int)((ip >> 24) & 0xff);            b[1] = (int)((ip >> 16) & 0xff);            b[2] = (int)((ip >> 8) & 0xff);            b[3] = (int)(ip & 0xff);            x=Integer.toString(b[0])+"."+Integer.toString(b[1])+"."+Integer.toString(b[2])+"."+Integer.toString(b[3]);             return x;      }}
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