生产者消费者模式代码简单实现

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看见有些作者在书上用synchronized同步锁去实现，利用wait()和notify()发信号。

其实锁方法是没办法并发的，这样做会把并行变成串行计算了。

信号量最好是创建一个新的类包含生产者和消费者的信号，再使用关键字volatile保证有序性。

代码如下:

public class Main {    public static void main(String[]args){        LinkedList<Integer>queen = new LinkedList<Integer>();        Sign sign = new Sign();        sign.iniSign();        new Thread(new Business(new Productor(),queen,500,100,sign)).start();        new Thread(new Business(new Customer(),queen,5,1000,sign)).start();    }}

/** * 信号 */public class Sign {    public  volatile int sign_p = 0;    public  volatile int sing_c = 0;    public void iniSign(){        this.sign_p = 1;        this.sing_c = 0;    }}

public class Business implements Runnable {    Person person;    LinkedList<Integer> queen;    int len;    int time;    Sign sign;    public Business(Person person,LinkedList<Integer> queen, int len,int time,Sign sign) {        this.person = person;        this.queen = queen;        this.len = len;        this.time = time;        this.sign = sign;    }    @Override    public void run() {        person.doThis(queen,len,time,sign);    }}

public  interface Person {    void doThis(LinkedList<Integer>queen,int len,int time,Sign sign);}

/** * 消费者，如果队列无数据，无法消费 */public class Customer implements Person {    public synchronized void doThis(LinkedList queen, int len, int time, Sign sign) {        System.out.println("消费者就绪");        while (true) {            while (sign.sing_c == 0) {            }            try {                Thread.sleep(time);            } catch (InterruptedException e) {            }            if (queen.size() > 0) {                System.out.println("消费者消费数据: " + queen.removeFirst());                sign.sign_p = 1;//释放生产信号            } else {                sign.sing_c = 0; //冻结消费信号            }        }    }}

public synchronized void doThis(LinkedList<Integer> queen, int len, int time,Sign sign) {        System.out.printf("生产者就绪");        int i = 0;        while (true) {            while(sign.sign_p == 0){//                System.out.println("生产者阻塞！！！");            }            try {                Thread.sleep(time);            } catch (InterruptedException e) {            }            if (queen.size() < len) {                queen.addLast(i);                System.out.println("生产者，生产数据： " + i++);                sign.sing_c = 1;//释放消费信号            } else {                sign.sign_p = 0; //冻结生产信号            }        }    }}

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