leetecode 303|304. Range Sum Query

303. Range Sum Query - Immutable

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive.

Example:

Given nums = [-2, 0, 3, -5, 2, -1]sumRange(0, 2) -> 1sumRange(2, 5) -> -1sumRange(0, 5) -> -3

Note:

1. You may assume that the array does not change.
2. There are many calls to sumRange function

sum[i] 存前i项和

class NumArray {public:    NumArray(vector<int> nums)     {        int k = nums.size();        if (k == 0) return;        sum.push_back(nums[0]);        for (int i = 1; i < k ; i++)        {            sum.push_back(sum.back() + nums[i]);        }    }    int sumRange(int i, int j)     {        if (i == 0)            return sum[j];        return sum[j] - sum[i-1];           }private:    vector<int> sum;};/** * Your NumArray object will be instantiated and called as such: * NumArray obj = new NumArray(nums); * int param_1 = obj.sumRange(i,j); */

304. Range Sum Query 2D - Immutable

Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2).

The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, col2) = (4, 3), which contains sum = 8.

Example:

Given matrix = [  [3, 0, 1, 4, 2],  [5, 6, 3, 2, 1],  [1, 2, 0, 1, 5],  [4, 1, 0, 1, 7],  [1, 0, 3, 0, 5]]sumRegion(2, 1, 4, 3) -> 8sumRegion(1, 1, 2, 2) -> 11sumRegion(1, 2, 2, 4) -> 12

Note:

1. You may assume that the matrix does not change.
2. There are many calls to sumRegion function.
3. You may assume that row1 ≤ row2 and col1 ≤ col2.

class NumMatrix {public:    NumMatrix(vector<vector<int>> matrix)     {        int row = matrix.size();        if (row == 0) return;        int col = matrix[0].size();        for (int j = 0; j < row; j++)            sum.push_back(vector<int> (col, matrix[0][0]));        for (int j = 1; j < col; j++) //第一行            sum[0][j] = sum[0][j-1] + matrix[0][j];        for (int i = 1; i < row; i++) //第一列            sum[i][0] = sum[i-1][0] + matrix[i][0];        for (int i = 1; i < row; i++)        {            for (int j = 1; j < col; j++)            {                sum[i][j] = sum[i - 1][j] + sum[i][j - 1] - sum[i-1][j-1] + matrix[i][j];            }        }                for (int i = 0; i < row; i++)        {            for (int j = 0; j < col; j++)                cout<<sum[i][j]<<" ";            cout<<endl;        }    }        int sumRegion(int row1, int col1, int row2, int col2)     {        int k1 = vaild(row2, col1 - 1);        int k2 = vaild(row1 - 1, col2);        int a1 = vaild(row1 - 1, col1 - 1);        return sum[row2][col2] + a1 - k1 - k2;    }     int vaild(int i, int j)    {        int row = sum.size();        int col = sum[0].size();        if (i >= 0 && i < row && j >= 0 && j < col)            return sum[i][j];        return 0;    }private:    vector<vector<int>> sum;};/** * Your NumMatrix object will be instantiated and called as such: * NumMatrix obj = new NumMatrix(matrix); * int param_1 = obj.sumRegion(row1,col1,row2,col2); */