ES6_数据结合map

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<!DOCTYPE html><html><head><meta charset="UTF-8"><title></title></head><body>//一：创建一个集合，基本用法可以用来去重<!--let name='张三',age='18',sex='nan';--><script type="text/javascript">let obj1={a:1},obj2={b:2},obj3={}obj3.name='天空';obj3[obj1]='李四';obj3[obj2]='王五';console.log(obj1.toString())//[object Object]console.log(obj2.toString())//[object Object]console.log(obj1.toString()==obj2.toString())//true//发现不管什么都会被转成字符串，所以需要map来解决//let obj1={a:1},obj2={b:2}   const map= new Map([   ['name','张三'],   ['age',9],   ['sex','男'],   [obj1,'今天是个好天气'],   [obj2,'适合敲代码'],   [[1,2],'订单']   ])   console.log(map)//Map(6) {"name" => "张三", "age" => 9, "sex" => "男", Object {a: 1} => "今天是个好天气", Object {b: 2} => "适合敲代码"…}//set和getmap.set('friend',['赵六','力气']).set(['dog'],'小花');console.log(map);console.log(map.get('name'));console.log(map.get(obj1))//////delete//map.delete(obj2)//console.log(map)////has//map.has();////clear//map.clear();//map.keys();//map.values();//console.log(map.entries())////遍历map.forEach(function(value,index){console.log(value);console.log(index)})</script></body></html>
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