2673 3-4 计算长方形的周长和面积

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3-4  计算长方形的周长和面积

Time Limit: 1000MS Memory Limit: 65536KB

Problem Description

通过本题的练习可以掌握拷贝构造函数的定义和使用方法;
设计一个长方形类Rect,计算长方形的周长与面积。类中有私有数据成员Length(长)、Width(宽),由具有缺省参数值的构造函数对其初始化,函数原型为:Rect(double Length=0, double Width=0); 再为其定义拷贝构造函数,形参为对象的常引用,函数原型为:Rect(const Rect &); 编写主函数,创建Rect对象r1初始化为长、宽数据,利用r1初始化另一个Rect对象r2,分别输出对象的长和宽、周长和面积。
 
 
要求: 创建对象 Rect r1(3.0,2.0),r2(r1);

Input

输入两个实数,中间用一个空格间隔;代表长方形的长和宽

Output

共有6
分别输出r1的长和宽;r1的周长;r1的面积;r2的长和宽;r2的周长;r2的面积;注意单词与单词之间用一个空格间隔

Example Input

56 32

Example Output

the length and width of r1 is:56,32the perimeter of r1 is:176the area of r1 is:1792the length and width of r2 is:56,32the perimeter of r2 is:176the area of r2 is:1792

Hint

 

输入-7.0 -8.0

输出

the length and width of r1 is:0,0

the perimeter of r1 is:0

the area of r1 is:0

the length and width of r2 is:0,0

the perimeter of r2 is:0

the area of r2 is:0


#include <bits/stdc++.h>using namespace std;class group{    public:        group()        {            length = 0;            width =0;        }        group(group &r1)        {            length = r1.length;            width = r1.width;        }        void get_in()        {            cin >> length >> width;            if(length < 0||width  < 0)            {                length = 0;                width  = 0;            }        }        void put_out1()        {            cout << "the length and width of r1 is:";            cout << length << ',' << width << endl;            cout << "the perimeter of r1 is:";            cout << 2*(length+width) << endl;            cout << "the area of r1 is:";            cout << length * width << endl;        }        void put_out2()        {       cout << "the length and width of r2 is:";            cout << length << ',' << width << endl;            cout << "the perimeter of r2 is:";            cout << 2*(length+width) << endl;            cout << "the area of r2 is:";            cout << length * width << endl;        }    private:        double length, width;};int main(){    group r1,r2;    r1.get_in();    r2 = r1;    r1.put_out1();    r2.put_out2();    return 0;}


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